Heating potassium chlorate produces potassium chloride and oxygen gas. The balanced equation for this decomposition reaction is below. Calculate how many moles of oxygen gas are formed from 6.32 grams of potassium chlorate? 2 KClO3 = 2KCl + 3 O2

The reaction forms 0.0763 mol of ##”O”_2##.

The equation is ##”2KClO”_3 → “2KCl” + “3O”_2##

Step 1. Calculate the moles of ##”KClO”_3##.
##6.23 cancel(“g KClO₃”) × (“1 mol KClO”_3)/(122.55 cancel(“g KClO₃”)) = “0.050 84 mol KClO”_3##

Step 2. Use the molar ratio from the equation to calculate the moles of ##”O”_2##.
##0.050 84 cancel(“mol KClO₃”) × (“3 mol O”_2)/(2 cancel(“mol KClO₃”)) = “0.0763 mol O”_2##

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