The reaction forms 0.0763 mol of ##”O”_2##.

The equation is ##”2KClO”_3 → “2KCl” + “3O”_2##

Step 1. Calculate the moles of ##”KClO”_3##.

##6.23 cancel(“g KClO₃”) × (“1 mol KClO”_3)/(122.55 cancel(“g KClO₃”)) = “0.050 84 mol KClO”_3##

Step 2. Use the molar ratio from the equation to calculate the moles of ##”O”_2##.

##0.050 84 cancel(“mol KClO₃”) × (“3 mol O”_2)/(2 cancel(“mol KClO₃”)) = “0.0763 mol O”_2##