How do you evaluate ##arcsin(sqrt 3/2)##?

##arcsin(sqrt(3)/2)=60°=pi/3##

##sqrt(3)/2## is a known value, and the main angle ##alpha## that has ##sin(alpha)=sqrt(3)/2## is ##alpha=60°=pi/3##.
Because arcsin is a function ##RR->[-1;1]##, we take only the value ##alpha=pi/3##, without the periodic values.
So ##arcsin(sqrt(3)/2)=60°=pi/3##.

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