How do you find the 6 trig functions of 330 degrees?

Trig unit circle gives:
##sin (330) = sin (360 – 30) = -sin 30 = -1/2## (trig table)
##cos (330) = cos (360 – 30) = cos 30 = (sqr3)/2##(trig table)
##tan (330) = (-1/2)(2/(sqr3)) = -1/(sqr3) = -(sqr3)/3##
##cot (330) = -sqr3##
##sec (330) = 2/(sqr3) = (2.sqr3)/3##
##csc (330) = -2##

Posted in Uncategorized

Leave a Reply

Your email address will not be published. Required fields are marked *

You may use these HTML tags and attributes:

<a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <s> <strike> <strong>