How do you write ##3^2=9## in logarithmic form?

It is ##log_3 9=2##

By definition the logarithmic form ##log_b x=y## is equivalent to the exponential form ##b^y=x##
Hence from the given ##3^2=9## you have ##b=3## ,##y=2## , ##x=9##
hence the logarithmic form is ##log_3 9=2##

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