What is the product of the aldol condensation between cyclopentanone and 4-methylbenzaldehyde?

The product is probably (##2E,5E##)-2,5-bis(4-methylbenzylidene)cyclopentanone.

The aldol condensation involves attack of an enolate ion on the base of a carbonyl compound to form a β-hydroxycarbonyl compound (an aldol).

(from www.chem.ucla.edu)
The aldol can then dehydrate to form an α,β-unsaturated carbonyl compound.
The process requires an active methylene adjacent to a carbonyl group.

If there are two active methylenes, the condensation can occur on each side of the carbonyl group.
For example, benzaldehyde with acetone gives dibenzalacetone.

By analogy, I predict that 4-methylbenzaldehyde with cyclopentanone will form
(##2E,5E##)-2,5-bis(4-methylbenzylidene)cyclopentanone.

The ##E,E## isomer should be more stable because the steric interactions of the ortho hydrogens with the ##”H”## atoms on the cyclopentane ring are smaller than those with the carbonyl oxygen

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